$\frac{9}{3}$
$\int x^3\left(2+3x^4^2\right)dx$
$-k+2\left(2k-5\right)$
$\left(2\cdot10-10^3+3\cdot10^2\right)$
$\lim_{x\to\infty}\left(\frac{x^2-x-8}{e^{2x}}\right)$
$+7=12$
$\lim_{x\to0}\left(\frac{6x+8\sqrt{9x-3}}{6}\right)$
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