y=(3+5x)2y=\left(3+5x\right)^2y=(3+5x)2
limx→−3(6x2−3x+6)\lim_{x\to-3}\left(6x^2-3x+6\right)x→−3lim(6x2−3x+6)
y′y−2=x2y'y^{-2}=x^2y′y−2=x2
∫0∞(1(x−1)(x−3))dx\int_0^{\infty}\left(\frac{1}{\left(x-1\right)\left(x-3\right)}\right)dx∫0∞((x−1)(x−3)1)dx
∫018.53π(0.89)2dx\int_0^{18.53}\pi\left(0.89\right)^2dx∫018.53π(0.89)2dx
(4x2−1)+(x3−x2+6x−2)\left(4x^2-1\right)+\left(x^3-x^2+6x-2\right)(4x2−1)+(x3−x2+6x−2)
x2+2x−3x+3limx→0(−3)\frac{x^2+2x-3}{x+3}\lim_{x\to0}\left(-3\right)x+3x2+2x−3x→0lim(−3)
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