$$-5\left(2y+3\right)$$

$$f\left(x\right)=5x^3\left(x^2-7\right)$$

$$3\cdot\left(x-6\right)-8,\:para\:x=9$$

$$\int\left(x^2\left(16-x^2\right)^{\frac{-1}{2}}\right)dx$$

$$\int\frac{1}{2x^2+4x+7}dx$$

$$\frac{x^2}{x+3}+\frac{x-6}{x+3}$$

$$\frac{\left(5^4\right)\:\left(5^2\right)}{\left(5^4\right)\left(5\right)}$$