$\left(\frac{x^4-8}{x^3+2x^2}\right)$
$\left(y+y+y\right)$
$2x^2+24$
$\sqrt[3]{5^9}+\sqrt[8]{16^4}$
$3x^2-2x+1=0$
$-12x-48$
$\left(-3x^2+9\right)\left(5x+2\right)$
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