12+4x\frac{1}{2+4x}2+4x1
2m3⋅(−4m3)2m^3\cdot\left(-4m^3\right)2m3⋅(−4m3)
−(x+4)=−x+y-\left(x+4\right)=-x+y−(x+4)=−x+y
x−63≤x+4\frac{x-6}{3}\le x+43x−6≤x+4
9r−17=199r-17=199r−17=19
ddxx1 y2 + 4 x3 − 5 y3 = −122\frac{d}{dx}x^1\:y^2\:+\:4\:x^3\:-\:5\:y^3\:=\:-122dxdx1y2+4x3−5y3=−122
sen4 −cos41−cosx=1\frac{sen^{4\:}-cos^4}{1-cosx}=11−cosxsen4−cos4=1
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