$\frac{dy}{dx}=-8a+16$
$2a+b=40$
$7t^5-6t^5$
$\int\:\frac{8}{x\left(7+12\ln\:\left(x\right)\right)^9}dx$
$\frac{d}{dx}\left(\frac{\left(y+6\right)}{\left(6y^2+x\right)}\right)$
$5x+1>6$
$\int\:\frac{3xe^{\sqrt{x^2+9}}}{\sqrt{x^2+9}}dx$
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