$\sqrt[4]{x^8}y^{12}$
$\frac{x^3}{x^2-9}$
$6x^2-60x+24=0$
$\left(3x-2y\right)\left(x+4y\right)$
$-5<x:2-3$
$\frac{-1}{y\sqrt{y^2-1}}dy=\frac{-1}{\sqrt{1-x^2}}dx$
$\left(8-y^3\right)^2$
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