$\frac{1-1}{\sqrt{3x-2-1}}$
$x\frac{dy}{dx}=x^3+4\cdot x^3y$
$( 2 x + 4 ) ( x - 2 )$
$1-tan^2\frac{x}{2}=\frac{2cosx}{1+cosx}$
$\left(8b+4b+7b\right)-\left(3b+9b-2b\right)$
$\sqrt{14\left(x+h\right)+1}-\sqrt{14x+1}$
$dx-x^3dy=0$
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