$\left(x^3+8\right)\left(x^4-16\right)\left(x^2-y^2-4x+4\right)$
$21m^2n-3m^2n^3+7m^4n^2$
$\lim_{x\to\infty}\left(\frac{1}{3}.\sqrt{5x^6-2}\right)$
$-6+4-\left(-1\right)$
$\frac{4x+31}{3}=5$
$\frac{4}{\sqrt{4-16x^2-8x}}$
$\left(2+3i\right)\cdot\left(-1-i\right)$
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