$\int\frac{\left(2+4x\right)}{1+x^2}dx$
$\int tanh\left(2x\right)sech\left(2x\right)dx$
$\frac{dy}{dx}=-2y\left(7-y\right)$
$\frac{6x^2+42x+38}{x+6}$
$5+2\left(3x-4\right)-x$
$4x+7\le35$
$139,920\left(\frac{0.045}{12}\right)$
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