$16-8x+4x^2$
$\left(ab^2\right)^3$
$\frac{dy}{dx}=3xe^{\frac{x}{y}}$
$7\left(8-23\right)$
$\:m^3n^4\:+n^4m^3$
$f\left(x\right)=\left(x-2\right)\left(x+5\right)\left(2x-3\right)\left(3-x\right)$
$\frac{dy}{dx}=ye^x$
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