$2,5^{2,5-3}$
$2x+8<-8$
$\left(8\right)\cdot\left(-4\right)\cdot\left(-7\right)$
$\frac{3x^2y-8x}{x+2}$
$2+1+8-11$
$\left(-5+9\right)-\left(-10-12\right)$
$\int\frac{x}{\left(x^2-6x+13\right)^2}dx$
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