$\lim_{x\to0}\left(cos\left(x\right)+2x\right)^{\frac{1}{2}}$
$-6-\left(-19\right)$
$x^2+16x+16=0$
$-8+5-\left(9+12-15\right)-24$
$5000\:\left(1+\frac{0.1}{2}\right)^{-n\cdot2}$
$\frac{2x-1}{x+3}+1\le0$
$\int\frac{4\sin^2x\cos x}{5}dx$
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