$\frac{dt}{dx}+x^2=x$
$\int\frac{4x}{x^2+5x+6}dx$
$4a^{2}+12a+36$
$\frac{4}{5}^{-2}$
$x^2-2x+1=16$
$\frac{4}{9}x^6y^{10}+\frac{x^3y^5z^4}{3}\frac{z^8}{16}$
$\frac{dy}{dx}=\frac{\left(2x+1\right)^2}{y}$
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