$\frac{2x^5+3x^3+3x-6}{x^2+1}$
$x^2-6x\ge\:-9$
$\left(-36\right)\left(-6\right)$
$\left(b^{-2}\right)^{-10}$
$10b-40ab^2$
$\frac{x^{10-1}}{x-1}$
$x+14=16$
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