$\frac{\left(-4^n\right)}{\sqrt{n}}\left(x+1\right)^n$

$\left(4y+2x^2\right)\left(2x^2-4y\right)$

$\left(\frac{2}{3}a^2+3b^4\right)\left(\frac{2}{3}a^2-3b^4\right)$

$x^{2}+13x+40$

$x^2+6x+11=3$

$\sin^{2}\alpha-\cos^{2}\alpha=\cos\alpha$

$\left(y^2-4xy\right)dx+\left(2xy-2x^2\right)dy=0$