$3-4\left(2^0-6^1+1^9\right)^2$
$\left(-1\right)\:+\:\left(-1\right)\:\cdot\:\left(-2\right)$
$\sec\left(x\right)^2+\tan\left(x\right)^2+1=\frac{2}{\cos\left(x\right)}$
$\left(-9\right)\left(-12\right)\left(-2\right)$
$\int\left(3x-5\right)e^{2x}dx$
$\tan\left(2\right)+\cot\left(2\right)+2$
$15x^2-240x$
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