cos(x)2−1⋅tan(x)2=1−sec(x)2\cos\left(x\right)^2-1\cdot\tan\left(x\right)^2=1-\sec\left(x\right)^2cos(x)2−1⋅tan(x)2=1−sec(x)2
y⋅ln(x)⋅dydx=(y+1x)(y+1x)y\cdot ln\left(x\right)\cdot\frac{dy}{dx}=\left(\frac{y+1}{x}\right)\left(\frac{y+1}{x}\right)y⋅ln(x)⋅dxdy=(xy+1)(xy+1)
du+5udu=5xdxdu+5udu=5xdxdu+5udu=5xdx
5−x>−65-x>-65−x>−6
1+x1−x2\frac{1+x}{1-x^2}1−x21+x
∫25−16x288x2dx\int\frac{\sqrt{25-16x^2}}{88x^2}dx∫88x225−16x2dx
(3x−2)⋅(3x+2)=77\left(3x-2\right)\cdot\left(3x+2\right)=77(3x−2)⋅(3x+2)=77
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