$\frac { 4 x ^ { 3 } + 4 x - 12 } { 2 x + 4 }$
$4x^2+8x+1=5$
$\left(-6\right)\left(+6\right)\left(-6\right)\left(-6\right)\left(-6\right)\left(-6\right)$
$\left(+318\right)+\left(+146\right)+\left(+189\right)$
$x^2+1\frac{1}{x^2}$
$-ln\left(3x+4\right)+2ln\left(x+1\right)$
$\left(x^4\right)^{-3}\cdot2x^4$
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