$\frac{\left(2x^5+4x\right)}{x-2}$
$x^2y^2+4x+4$
$sinx\left(tan\left(x\right)+csc\left(x\right)\right)=\frac{\left(sin\left(x\right)+cos\left(x\right)\right)}{cos\left(x\right)}$
$\frac{2x^4-x^3+x^2-10}{x-3}$
$5+3y^2=2x^3$
$\int\left(3x^2-2x\right)^5\left(6x-2\right)dx$
$-\frac{861}{\left(-3\right)}$
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