$\frac{\left(s+3\right)}{\left(s+1\right)\left(s+2\right)}$
$\left(5a^2+4a-9\right)-\left(3a^2+6a-5\right)$
$\left(y-yx^2\right)\frac{dy}{dx}=\left(y-1\right)$
$4.5+0.46+3.25$
$\left(2x+3\right)\cdot\left(x+6\right)$
$y+x^2=6$
$\lim_{x\to0}\left(\frac{cos\left(3x-1\right)}{x^2}\right)$
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