$3\cos\left(x\right)-4=2$
$\lim_{x\to1}\left(\frac{1}{\ln\left(x\right)}-\frac{2}{x^2-1}\right)$
$a^2+b^2=27$
$\left(4ab\:3\:-\:8a\:2\:b\:2\:+\:9ab\:-\:15\:ab\:2\:\right)$
$4+1+7+2+1+1+8$
$\left(3+b\right)^3$
$\frac{dp}{dt}=\left(p\left(1-p\right)\right)$
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