$\frac{-1}{3\cdot\infty}$
$x^2+1=3x^2$
$\frac{-10-\left(-2-2^{3}\right)}{\sqrt{400}-5\left(-2\right)^{2}}$
$\left(-9+6\right)-\left(4-6\right)$
$\left(-8\right)\left(-\frac{5}{2}\right)$
$-4x\left(x-1\right)\left(x-2\right)$
$\cos\left(x-\frac{\pi}{3}\right)=0.5$
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