(x−1)(x+6)>0\left(x-1\right)\left(x+6\right)>0(x−1)(x+6)>0
limx→∞(1+2x+14x2−x)2x\lim_{x\to\infty}\left(1+\frac{2x+1}{4x^2-x}\right)\sqrt{2}xx→∞lim(1+4x2−x2x+1)2x
(3x−4)(x+3)−(x−2)2=3\left(3x-4\right)\left(x+3\right)-\left(x-2\right)^2=3(3x−4)(x+3)−(x−2)2=3
w2−16w+64w^2-16w+64w2−16w+64
3x2−(−x2−12)3x^2-\left(-x^2-12\right)3x2−(−x2−12)
y2−3y+4y^2-3y+4y2−3y+4
(x15+y15)(x3+y3)\left(x^{15}+y^{15}\right)\left(x^3+y^3\right)(x15+y15)(x3+y3)
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