56(6x+12)+1=23(9x−3)+4\frac{5}{6}\left(6x+12\right)+1=\frac{2}{3}\left(9x-3\right)+465(6x+12)+1=32(9x−3)+4
∫x3+x2+3x−2x2−x−6dx\int\frac{x^3+x^2+3x-2}{x^2-x-6}dx∫x2−x−6x3+x2+3x−2dx
sinx=1−cosx\sin x=1-\cos xsinx=1−cosx
(3a+2b)22\left(3a+2b\right)^22(3a+2b)22
x+−4=7x+-4=7x+−4=7
−8−w>−7-8-w>-7−8−w>−7
sin(83o)cos(7o) + cos(83o)sin(7o) sin\left(83o\right)cos\left(7o\right)\:+\:cos\left(83o\right)sin\left(7o\right)\:sin(83o)cos(7o)+cos(83o)sin(7o)
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