$2x-4<x+3$
$\sqrt{\left(1+3x\right)^2}>2$
$\left(10t^3+9\right)\left(3t^3-5\right)$
$2b\:-5\:=\:8b\:+\:1$
$19x^2-13x+15x-5x^2$
$\left(-\frac{\frac{2}{3}}{-\frac{1}{3}}\right)$
$4\left(-7n-3\right)-\left(8-n\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!