$\frac{5x+3}{2}\le\frac{3x+1}{4}$
$-25x^2y+32xy$
$36+-1+4$
$\int_1^{\infty}\left(x^{-\frac{3}{2}}\right)dx$
$\frac{r}{11}+3+r$
$\lim_{x\to\infty}\left(\frac{\left(1+e^{-x}\right)}{15+2x^2}\right)$
$5\sqrt{4x-3}=5x$
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