b(4)=243+2 b\left(4\right)=24^3+2\:b(4)=243+2
(x2−5)4\left(x^2-5\right)^4(x2−5)4
5∫tan(θ)2dθ5\int\tan\left(\theta\right)^2d\theta5∫tan(θ)2dθ
31−x5\frac{3}{1-x^5}1−x53
x dydx=y(x2+x)x\:\frac{dy}{dx}=y\left(x^2+x\right)xdxdy=y(x2+x)
x3−6x\frac{x^{3}-6}{x}xx3−6
−7⋅b=−210-7\cdot b=-210−7⋅b=−210
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