$$4x^{2+4x+1=9}$$

$$\lim_{x\to2}\left(\frac{2x^3-2x}{x^3-4x+4}\right)$$

$$9x^6-30x^3+25$$

$$4+-13+-8$$

$$x^2-13x-14$$

$$\left(8^{-3}\right)^4$$

$$\lim_{x\to\infty}\:\:\frac{\left(\left(2+x\right)x\right)}{\left(1+x\right)^{\left(1.5\right)}}$$