$\int\frac{4\tan^{-1}\left(x\right)}{x^2+1}dx$
$200,4\cdot32,08$
$\int4e^{\sqrt{x}}dx$
$9x^2-42x+49=0$
$-8^2+-\left(-7\right)\left(-1\right)$
$xy=y+\sqrt{y^2-x^2}$
$\int2\left(4x+3\right)dx$
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