$x-6>0$
$\left(a^4-6a^3+8a^2-7a+5\right)\left(-3a^2b^3\right)$
$\left(4x^m\right)\left(x+3\right)$
$5\left(8+x\right)+9$
$\lim_{x\to1}\left(\frac{x^3+5x^2-6}{x-1}\right)$
$\lim_{x\to-\infty}\left(\frac{x^{2}-5x+3}{\sqrt{x^{4}-2x^{2}-1}}\right)$
$-\frac{1}{3}\left(3n-12\right)\:-\frac{7}{10}\left(5n-2\right)$
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