$\frac{1-8x-16x^2}{4x-1}$
$\left(a^2+3b^2\right)^2$
$\int5xe^8\:dx$
$x\:+\:13xy\:-\:6x\:-\:2x\:+\:8xy\:\:+\:y\:-\:2xy\:$
$-2\left(1+\frac{\left(-9\right)}{3}\right)$
$y'-xy^2=2xy$
$\vec{t}>\frac{t}{2+x}=\frac{2}{s}$
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