$4x\left(\sin^2\left(x\right)-\cos\left(3x\right)\right)$
$\int\left(56sec\left(7x\right)tan\left(7x\right)\right)dx$
$\left(3x-1\right)^2-\left(3x+1\right)^2\:$
$\frac{m-n}{n}$
$\left(3x^2y\right)\cdot\left(7x^3y^3\right)$
$a^2+b^2=12$
$-2x^4yz-xy^2+7x^4y^5$
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