$3\left(1-cos^2x\right)=3\tan^2\left(x\right)$
$b^2-10b+21$
$-3000+1000$
$-4x^2-8x+60$
$x+11=-23$
$\frac{\ln\left(\infty\right)}{\sqrt[3]{\infty\:}}$
$\:sin\left(\theta\:-\pi\:\right)=-sin\theta\:$
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