$e^2^{\infty}$
$l^{-1}$
$\int\left(\frac{1}{\left(1-3t\right)^4}\right)dt$
$\left(m^2+6\right)\cdot\left(m^2-2\right)$
$\frac{dy}{dx}=4x^8y^6$
$9x^2+4z^2+18x-36y-8z+13=0$
$\left(8x-2\right)dx\:+\left(4y-1\right)dy\:=\:0$
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