4x+8x−12y−24y4x+8x-12y-24y4x+8x−12y−24y
36x2+60x⋅2536x^2+60x\cdot2536x2+60x⋅25
secθ−cosθsinθ+1=tanθ\sec\theta-\frac{\cos\theta}{\sin\theta+1}=\tan\thetasecθ−sinθ+1cosθ=tanθ
1,875+3,1251,875+3,1251,875+3,125
2x3+4x2−52x2−2\frac{2x^3+4x^2-5}{2x^2-2}2x2−22x3+4x2−5
∫40x4csc2(9x5+10)dx\int40x^4\csc^2\left(9x^5+10\right)dx∫40x4csc2(9x5+10)dx
13x−5\frac{1}{3x^{-5}}3x−51
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!