$\left(x^2-3x\right)\left(\frac{3}{5}x^{-1}\right)$
$\lim_{x\to0}\left(x-3\right)\cdot\ln\left(x-3\right)$
$x+4x+8$
$x^2-121x=0$
$54-\left(-32\right)$
$\sqrt{12+2+4}$
$\left(5x-9\right)^2$
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