$\frac{2x^2+11x+8}{x+4}$
$\int\:\frac{1}{\:9x^2-16}dx$
$x^2-2x-10=0$
$\left(28\right)\left(11\right)$
$\frac{2x+6}{2}-2x=6$
$144\:a\:^2\:\:100\:b^2$
$\lim_{x\to\infty}\left(\frac{2}{3}\right)^x$
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