$\left(4\right)^5\:.\:\left(-2\right)^{12}$
$\frac{5x}{2}=15$
$3\sin^2x-\sin x-4$
$22m-33=11$
$\frac{7^9}{7^9}$
$20^3$
$+4-\left(-6\cdot\left(+2\right)\right)-7$
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