$\left(2p-3q+4r\right)^2$
$\lim_{x\to2}\left(\frac{x^2+8}{x-2}\right)$
$4x^2+12x^3-24x^5-8x^5$
$\sec\left(x\right)^2+\csc\left(x\right)^2=\sin^2\left(x\right).\sec^2\left(x\right)$
$9x^2-30x+16$
$\int\frac{1}{-3x+2+x^3}dx$
$\frac{dx}{df}=4\left(x^2+1\right)x\frac{\pi}{4}=1$
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