$\frac{d}{dx}\left(x^5\left(4-ln\left(x^5\right)\right)\right)$
$2.5x=.5\left(4x+12\right)$
$xz^3\cdot4x^4z^5$
$4^5\cdot4^{12}$
$5x^4y^2z^2;\:x=3;\:y=-2;\:z=1$
$\int_0^1\left(x^{-5}\right)dx$
$\left(m+15\right)\left(m+1\right)$
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