$-4=\csc\left(\theta\right)$
$\left(x+5\right)=5$
$5\infty2$
$\left(3x-4\right)+\left(3x+4\right)$
$4x^6-9a^8$
$-11\:+\:4\left(b\:+\:2c\right)\:+\:5\:-\:7b$
$\left(x+6\right)^2-\left(x-1\right)^2$
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