$\frac{1+\cos x-\cos^2x}{\sin x}=\sin x+\cot x$

$\int_0^{\frac{3\pi}{2}}\left(\sin\left(\frac{2}{3}\right)x\right)dx$

$9\int\left(\cos^2\left(x\right)\right)dx$

$25x^2+14x+4=0$

$-9-5+12-8+2$

$4\:\cdot\left[\left(+5\right)\:+\:\left(-7\right)\right]\:-\:\left(-3\right)\cdot\:\left[7\:-\:\left(+3\right)\right]$

$\left(4c+6\right)\left(4c-2\right)$