$\frac{d^2y}{dx^2}+5\:\frac{dy}{dx}=0$
$\left(4+i\right)\left(7-3i\right)$
$\lim\:_{x\to\:0}\:\frac{\tan\left(4x\right)}{x}$
$8x^2=128$
$\frac{x^5-x^4+x^2-2}{x^2+1}1$
$2x-1^2$
$x+2y-42=-4$
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