$3x-4=x+6$
$x^2+8x+2^7$
$3\sqrt{g^3}+6^2f^4+x$
$8\left(m+3\right)-p\left(3+m\right)$
$\frac{1+\sec\left(x\right)^2}{1+\tan\left(x\right)^2}=\frac{3}{2}$
$\int\left(5x^4+7\right)x^3dx$
$\left(3x+y+1\right)^2$
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