$\lim_{x\to0}\left(x^3-3x^2+2x+4\right)$
$\lim_{x\to infinity}\left(\frac{e^x}{e^{3x}}\right)$
$4a^2-1-a^2+4a$
$6-2x^2\ge-3x^2+2$
$\lim\:_{x\to\:\infty\:\:}\sin\left(15\right)$
$\frac{x^2+7x-26}{x+3}$
$3x+\frac{4y}{9}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!