$24y^2-18y^2+30y$
$\frac{d}{dx}8=\frac{5x^2}{4y}$
$7x-6<-5x+1$
$\frac{3x^{-1}y^{-3}}{2x^4y^0}$
$18y^{2}+15y-18$
$\left(\frac{\left(4x^3-6x\right)}{\left(-6\right)}\right)^3$
$\frac{-150}{3}$
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