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$2a^2+a$
$\int\frac{w\left(w^3-4\right)}{\sqrt{w^5-10w^2+8}}dx$
$\frac{dy}{dx}=\frac{10x}{\sqrt{25-y^2}}$
$5\cdot4-2-4:\:2$
$3x^2+5x-x^2-x-2x^2$
$tan\left(\frac{x}{2}\right)=0$
$\int\left(\sinh\:\left(4x\right)\sinh\:\left(3x\right)\right)dx$
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