$\left(5w^2-2x^3\right)^2$
$1+tan^2x=secx$
$\frac{\left(1+\cos\left(x\right)\left(1-\cos\left(x\right)\right)\right)}{\sin^2\left(x\right)}$
$m^5-7m^4+11m^3+19m=0$
$\int\frac{-5x}{x^2+15x+50}dx$
$\lim_{x\to2}\left(\frac{x^2-1}{\sqrt{x}-1}\right)$
$15^2\cdot3.1416$
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