Exercise
$\left(x+4\right)\left(x-4\right)+15=x+5$
Step-by-step Solution
Learn how to solve limits by direct substitution problems step by step online. Solve the quadratic equation (x+4)(x-4)+15=x+5. The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Subtract the values 15 and -16. Group the terms of the equation by moving the terms that have the variable x to the left side, and those that do not have it to the right side. Add the values 5 and 1.
Solve the quadratic equation (x+4)(x-4)+15=x+5
Final answer to the exercise
$x=-2,\:x=3$